化简：(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)RT,化简：(1/√_数学解答

化简：(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
RT,化简：(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))(n为正整数,且n≠2)
坐等.

人气：125 ℃　时间：2020-05-20 23:15:36

解答

(1/√2+√4)+(1/√4+√6)+……+(1/(√2n-2)+(√2n))=（√2-√4）/[(√2+√4)(√2-√4)]+(√4-√6)/[(√4+√6)(√4-√6)]+……+(√2n-2-√2n)/[(√2n-2+√2n)(√2n-2-√2n)]=(√2-√4)/(-2)+(√4-√6)/(-2)+……+(√2...