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化简:[(x+y)^2n]^4÷(-x-y)^2n+1(n为正整数)
人气:337 ℃ 时间:2020-06-21 21:51:22
解答
[(x+y)^2n]^4÷(-x-y)^2n+1
=-(x+y)^8n÷(x+y)^(2n+1)
=-(x+y)^(8n-2n-1)
=-(x+y)^(6n-1)
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