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求证:sin^2acos^2b-cos^2asin^2b=cos^2b-cos^2a
人气:364 ℃ 时间:2020-02-12 20:16:07
解答
证明:左边=sin^2acos^2b-cos^2asin^2b=(1-cos^2a)cos^2b-cos^2a(1-cos^2b)=cos^2b-cos^2acos^2b-cos^2a+cos^2acos^2b=cos^2b-cos^2a右边=cos^2b-cos^2a左边=右边所以sin^2acos^2b-cos^2asin^2b=cos^2b-cos^2a...
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