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化简sin^2asin^2b+cos^2acos^2b-1/2(cos2acos2b)=
感觉这题有点怪啊
人气:127 ℃ 时间:2020-03-24 04:34:59
解答
cos2acos2b=(cos^2a-sin^2a)(cos^2b-sin^2b)
所以化简得:1/2(sin^2asin^2b+cos^2acos^2b+cos^2asin^2b+sin^2acos^2b)
=1/2(sin^2a+cos^2a)(sin^2b+cos^2b)
=1/2
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