∫(1+x-1/x)e^(x+1/x)dx =∫e^(x+1/x)dx+∫(x-1/x)e^(x+1/x)dx =xe^(x+1/x)|-∫xde^(x+1/x) +∫(x-1/x)e^(x+1/x)dx =(3/2)e^(5/2)-∫x[e^(x+1/x)][1-(1/x²)]dx +∫(x-1/x)e^(x+1/x)dx =(3/2)e^(5/2)-∫[e^(x+1/...