若（x^2-y^2分之M）=(x^2-y^2分之2xy-y^2)+(x+y分之x-y）,则M=多少_数学解答

若（x^2-y^2分之M）=(x^2-y^2分之2xy-y^2)+(x+y分之x-y）,则M=多少

人气：179 ℃　时间：2020-06-05 11:23:45

解答

（x^2-y^2分之M）=(x^2-y^2分之2xy-y^2)+(x+y分之x-y）,M/(x²-y²)=(2xy-y²)/(x-y)(x+y)+(x-y)/(x+y)M/(x-y)(x+y)=(2xy-y²+x²-2xy+y²)/(x-y)(x+y)M/(x-y)(x+y)=x²/(x-y)(x+y)∴M=...