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1.计算5a/(6a^2c)-7b/(12ac^2)+11c/8a^2b
2.计算[y/(x^2-xy)+x(y^2-xy)]/(xy)
3.计算{(b-c)/[(a-b)(a-c)]}+{(a-c)/[(b-a)(b-c)]}+{(a-b)/[(c-a)(c-b)]}
4.已知3x/(x^2-1)=A/(x+1)+B/(x-1),求A、B的值.
人气:389 ℃ 时间:2020-03-03 00:44:39
解答
(1) 5a/(6a^2c)-7b/(12ac^2)+11c/8a^2b =(20abc-14a^2b+33c^3)/(24a^2bc^2) (2) [y/(x^2-xy)+x(y^2-xy)]/(xy) =((y^2-x^2)/(xy(x-y))/(xy) =-(x+y)/(x^2y^2) (3) {(b-c)/[(a-b)(a-c)]}+{(a-c)/[(b-a)(b-c)]}+{(a-b)/...
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