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数学
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1,计算简化(sinβ)的四次+(cosβ)的四次 2,sin10°×cos20°×cos40°的解题过程
人气:391 ℃ 时间:2020-04-07 04:06:56
解答
一,sin^4a+cos^4a
=(sin²a+cos²a)²-2sin²acos²a
=1-(1/2)(2sinacosa)²
=1-(1/2)sin²2a
二:sin10°*cos20°*cos40°
=cos10°sin10°*cos20°*cos40°/cos10°
=(1/2)sin20°*cos20°*cos40°/cos10°
=(1/4)sin40°*cos40°/cos10°
=(1/8)sin80°/cos10°
=(1/8)cos10°/cos10°
=1/8
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