(2x+5)/(x2-1)=A/(x-1)+B/(x+1),
=A(x+1)/[(x-1)(x+1)]+B(x-1)/[(x+1)(x-1)]
=[(A-B)+(A+B)x]/(x²-1)
对应相等得
A-B=5
A+B=2
相加得
2A=7 A=7/2
相减得
2B=-3 B=-3/2