（1/5）^[ (log2 X)^2-1] < (1/5)^[ 2x(2+log底数为根号2 X)=> (log2 X)^2-1 > 2x(2+log底数为根号2 X),令log2 X = y=>y^2 -1 > 4 + 2( log2X/log2根号2)=> y^2 > 5 + 4y => y> 5 => x > 32