∫ (lnx-1)/x² dx
=-∫ (lnx-1) d(1/x)
=-[(lnx-1)/x-∫ 1/x d(lnx-1)]
=-(lnx-1)/x+∫ 1/x² dx
=-(lnx-1)/x-1/x+C
=-lnx/x+C