(kx-6)[x-(k+6)]=0x1=6/k x2=k+6由题,k>0(1) 6/k=k+6k²+6k-6=0k=√15-3(2)6/k=√2(k+6)k²+6k-√3=0 k=√(9+√3)-3(3)k+6=√2*6/kk²+6k-6√2=0k=√3+√6-3