1/(x-1)+2/(6y-3)=1
所以1/(x-1)+2/[3(2y-1)]=1
1/(2x-2)-1/(2y-1)=0
所以1/[2(x-1)]-1/(2y-1)=0
令a=1/(x-1),b=1/(2y-1)
所以a+(2/3)b=1
(1/2)a-b=0
b=(1/2)a
a=2b
代入a+(2/3)b=1
2b+(2/3)b=1
(8/3)b=1
b=3/8,a=2b=3/4
所以1/(x-1)=3/4
x-1=4/3,x=7/3
1/(2y-1)=3/8
2y-1=8/3
y=11/6
所以x=7/3,y=11/6