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数学
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方程组:(1/x+1)+(2/6y-3)=1 (1/2x-2)-(1/2y-1)=0,解x、y.
1/(x-1)+2/(6y-3)=1,1/(2x-2)-1/(2y-1)=0,那个错了,
人气:449 ℃ 时间:2019-12-08 19:52:56
解答
1/x+1)+(2/6y-3)=0得3y+x-6xy=0,由1 (1/2x-2)-(1/2y-1)=0得y-x=0,所以x=y=0或等于2/3由于x,y均为他母,所以不等于0所以x=y=2/3
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