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若 lim 2n—根号(4n^2-kn+3) =1,则k=?
人气:297 ℃ 时间:2020-05-28 06:46:03
解答
2n—根号(4n^2-kn+3)=(kn-3)/(2n+根号(4n^2-kn+3))lim 2n—根号(4n^2-kn+3)=lim(kn-3)/(2n+根号(4n^2-kn+3))=lim(k-3/n)/(2+根号(4-k/n+3/n^2))=(k-0)/(2+根号(4-0+0))=k/4=1k=4
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