计算(1)3x/8y×16y²/27x² (2)(2xy-x²)÷x-2y/xy 2x-6/x²-4x+4×2x-4/x-3
人气:404 ℃ 时间:2019-08-17 17:30:59
解答
(1)3x/8y×16y²/27x² =(3/8×16/27)×(y/x)=2y/9x(2)(2xy-x²)÷x-2y/xy =x(2y-x)×[xy/(x-2y)]=-x²y(3)2x-6/x²-4x+4×2x-4/x-3=2(x-3)/(x-2)²×2(x-2)/(x-3)=4/(x-2)
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