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计算x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3=
人气:181 ℃ 时间:2020-03-23 02:07:18
解答
x²+4/x+3+x²-x-6/x+3-2x²-2x-5/x+3
=(x²+4+x²-x-6-2x²-2x-5)/(x+3)
=(-3x-7)/(x+3)
=-(3x+7)/(x+3)
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