计算(lg√27+lg8-lg√1000)/lg1.2.lg1.2=lg12-1？_数学解答

计算(lg√27+lg8-lg√1000)/lg1.2.
lg1.2=lg12-1？

人气：289 ℃　时间：2020-04-09 19:30:03

解答

(lg√27+lg8-lg√1000)/lg1.2
=（3/2lg3+3lg2-3/2)/(lg12-1)
=3/2(lg3+2lg2-1)/(lg12-1)
=3/2(lg12-1)/(lg12-1)
=3/2