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第一个5/x-3-2x-5/x^2-3x 第二个x^2/x^2-y^2-x/x+y 用分式的加减法
人气:206 ℃ 时间:2020-03-19 17:04:58
解答
5/(x-3)-(2x-5)/(x^2-3x)=5x/x(x-3)-(2x-5)/x(x-3)=(5x-2x+5)/x(x-3)=(3x+5)/x(x-3) x^2/(x^2-y^2)-x/(x+y )=x²/(x-y)(x+y)-x(x-y)/(x+y)(x-y)=(x²-x²+xy)/(x+y)(x-y)=xy/(x+y)(x-y)
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