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求极限lim(1+2x)(指数x分之1)(x→0)
人气:362 ℃ 时间:2020-03-24 19:46:38
解答
lim (1+2x)^(1/x)
=e^[lim (1/x)ln(1+2x)]
=e^[lim ln(1+2x)/x]
0/0型极限,用洛必达法则
=e^[lim (2/(1+2x))/1]
=e^[lim 2/(1+2x)]
=e^[lim 2]
=e^2
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