求函数y=7-4sinxcosx+2(cosx)^2-2(sinx)^2的最大及最小值
人气:267 ℃ 时间:2020-01-29 23:31:30
解答
y=7-4sinxcosx+2(cosx)^2-2(sinx)^2=7-2sin2x+2cos2x=7-2根号2sin(2x-π/4)
最大7+2根号2
最小7-2根号2
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