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已知m²-3m-1=0,则2m²-3m+m的-2次方=?
人气:307 ℃ 时间:2019-10-08 16:20:36
解答
2m^2-3m+m^(-2)
=m^2+m^(-2)+m^2-3m
=(m-1/m)^2+m^2-3m+2
∵m²-3m-1=0 显然m≠0
∴m²-3m=1 m-3-1/m=0 即 m-1/m=3
∴原式=(m-1/m)^2+m^2-3m+2
=3^2+1+2
=9+1+2=12
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