log (a) ab=1/p ,Log(a)a+Log(a)b=1/p,1+Log(a)b=1/pLog(a)b=(1-p)/p log (ab) a/b=(换底)=[Log(a)a/b]/Log(a)(ab)=[Log(a)a/b]/(1/p)=p[Log(a)a/b]=p[LOg(a)a-LOg(a)b]=p[1-(1-p)/p]=p-(1-p)=2p-1