已知x=1/x,求(x²-5/x-1+1)乘以x³-1/x²-2x除以(x+3)的值
人气:301 ℃ 时间:2020-06-18 12:44:39
解答
x=1/x则x=±1(x²-5/x-1+1)乘以x³-1/x²-2x除以(x+3)=(x²-5/x)X(x³-1/x²-2x)÷(x+3)=[(x^3-5)/x]X[(x^5-1-2x^3)/x^2]÷(x+3)=(x^3-5)(x^5-2x^3-1)/[x^3(x+3)]当x=1时=(1-5)(1-2-1)/...
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