x+2y+3z=3
3x+y+2z=7
2x+3y+z=2
求XYZ分别为多少
人气:334 ℃ 时间:2020-10-01 18:16:31
解答
X+2Y+3Z=3 (1)
3X+Y+2Z=7 (2)
2X+3Y+Z=2 (3)
(1)+(3)-(2)得:4Y+2Z=-2即:
2Y+Z=-1 (4)
(1)*2-(3)得:Y+5Z=4即
Y=4-5Z (5)
(5)代入(4)得:
Z=1代入(5)得:
Y=-1
将Z=1,Y=-1代入(1)得:
X=2
所以:
X=2
Y=-1
Z=1
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