| ab−2 |
∴a-1=0，ab-2=0，
解得a=1，b=2，
| 1 |
| ab |
| 1 |
| (a+1)(b+1) |
| 1 |
| (a+2)(b+2) |
| 1 |
| (a+2009)(b+2009) |
=
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 2010×2011 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2010 |
| 1 |
| 2011 |
=1-
| 1 |
| 2011 |
=
| 2010 |
| 2011 |
| ab−2 |
| 1 |
| ab |
| 1 |
| (a+1)(b+1) |
| 1 |
| (a+2)(b+2) |
| 1 |
| (a+2009)(b+2009) |
| ab−2 |
| 1 |
| ab |
| 1 |
| (a+1)(b+1) |
| 1 |
| (a+2)(b+2) |
| 1 |
| (a+2009)(b+2009) |
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 2010×2011 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 2010 |
| 1 |
| 2011 |
| 1 |
| 2011 |
| 2010 |
| 2011 |