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x²-y/ax-bx+ay-by=?
人气:308 ℃ 时间:2020-03-26 06:23:12
解答
ax-bx+ay-by
=(ax+ay)-(bx+by)
=a(x+y)-b(x+y)
=(a-b)(x+y)
原式=(x+y)(x-y)/(a-b)(x+y)
=(x-y)/(a-b)
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