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求∫ x^4-3x^2+5x-1 / x^3dx的不定积分?
人气:391 ℃ 时间:2020-04-16 08:24:38
解答
∫ x^4-3x^2+5x-1 / x^3dx
=∫ x^4-3x^2+5x-x^(-3)dx
=(1/5)x^5 - x^3 +(5/2)x^2 + (1/2)(x^-2)+c
如果这个题是:
∫ (x^4-3x^2+5x-1) / x^3dx
=∫x - 3/x + 5x^(-2) - x^(-3) dx
=(1/2)x² -3lnx -(5/x) +(1/2)x^(-2) +c
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