1 |
15 |
48×
1 |
15 |
16 |
5 |
1 |
5 |
10-5=5(分钟);
5分钟=
1 |
12 |
48×
1 |
12 |
答:A站到B站的距离3
1 |
5 |
(2)19-13=6分钟=
1 |
10 |
(3
1 |
5 |
1 |
10 |
=
36 |
5 |
1 |
10 |
=72(千米);
答:返回的速度是72千米.
(3)4+5+6=15(分钟)=
1 |
4 |
(3
1 |
5 |
1 |
4 |
=
36 |
5 |
=
288 |
5 |
=57.6(千米);
答:电车往返的平均速度是57.8千米.
故答案为:(1)3
1 |
5 |
1 |
15 |
1 |
15 |
16 |
5 |
1 |
5 |
1 |
12 |
1 |
12 |
1 |
5 |
1 |
10 |
1 |
5 |
1 |
10 |
36 |
5 |
1 |
10 |
1 |
4 |
1 |
5 |
1 |
4 |
36 |
5 |
288 |
5 |
1 |
5 |