如图,Rt△AB′C′是由Rt△ABC绕点A顺时针旋转得到的,连接CC′交斜边于点E,CC′的延长线交BB′于点F.
![](http://hiphotos.baidu.com/zhidao/pic/item/a5c27d1ed21b0ef417d168efdec451da81cb3e41.jpg)
(1)证明:△ACE∽△FBE;
(2)设∠ABC=α,∠CAC′=β,试探索α、β满足什么关系时,△ACE与△FBE是全等三角形,并说明理由.
(1)证明:∵Rt△AB′C′是由Rt△ABC绕点A顺时针旋转得到的,∴AC=AC′,AB=AB′,∠CAB=∠C′AB′,∴∠CAB+∠BAC′=∠C′AB′+∠BAC′,即∠CAC′=∠BAB′,∴∠ABB′=∠AB′B=∠ACC′=∠AC′C,∴∠ACC′=∠ABB...