√11...11(2n个1)-22...2(n个2)+1
=√11...11(2n个1)-2×11...1(n个1)+1
=√【11...11(n个1)-1】的平方
=11...11(n个1)-1
=11...110(n-1个1)答案是33...3（n个3），你答错了吧应该是这样：√11...11(2n个1)-22...2(n个2)=√11...11(n个1)*【100…001（n-1个0）-2）】=√【11...11(n个1)*99…99（n个9）=√11...11(n个1)*11...11(n个1)*9=11...11(n个1)*3=33...33(n个3)