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(6x+1)(4x+1)(3x+1)(2x+1)=41x^2速度,
人气:487 ℃ 时间:2020-03-20 10:17:23
解答
(6x+1)(4x+1)(3x+1)(2x+1)=41x^2(6x+1)(2x+1)(4x+1)(3x+1)=41x^2(12x^2+8x+1)(12x^2+7x+1)=41x^2(12x^2+1)^2+15x(12x^2+1)+56x^2=41x^2(12x^2+1)^2+15x(12x^2+1)+15x^2=0请检查题目是否有错,方法是这样....我做出来也这样如题目没错,还要做下去,用求根公式吧。不过会较复杂。你能解出来吗太复杂了,你自己试试吧。
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