不论x、y为何实数，代数式x2+y2+2x-4y+7的值总不小于______．
人气：412 ℃ 时间：2019-12-10 19:29:27
解答
∵x2+y2+2x-4y+7
=（x+1）2+（y-2）2+2≥2，
故不论x、y为何实数，代数式x2+y2+2x-4y+7≥2恒成立．
故答案为：2．
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