(2x-3)(2x-3)=x²-6x+9(2x-3)²=(x-3)²(2x-3)²-(x-3)²=0[(2x-3)+(x-3)][(2x-3)-(x-3)]=0(3x-6)x=0x(x-2)=0x=0或x=2(2x-1)²=(1+√2)²(2x-1)²-(1+√2)²=0[(2x-1)+(1+√2)]...