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先化简,再求值[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
人气:359 ℃ 时间:2020-05-12 12:58:19
解答
[a²/a²-b²-a²b/a²-b²*(a/ab+b²-b/a²+ab)]
={a²(/a²-b²)-a²b/(a²-b²)*(a²-b²)/[ab(a+b)]}
={a²/(a²-b²)-a/[(a+b)]}
=[a²-a(a-b)]/[(a+b)(a-b)]
=b/[a+b)(a-b)]
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