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sinx+cosx=m(m的绝对值<=根号2且m的绝对值不等于1)求(1)sin^3x+cos^3x(2)sin^4x+cos^4x的值
人气:475 ℃ 时间:2020-05-06 23:03:07
解答
sin^3x+cos^3x=(sinx+cosx)(sin^2-sinxcos+cos^2)=(sinx+cosx)(1-sinxcosx)=m(1-(m^2-1)/2)=3m/2-m^3/2
sin^4x+cos^4x=(sin^2x+cos^2x)^2-2sin^2xcos^2x=1-2sin^2xcos^2x=1-2[(m^2-1)/2]^2=1-(m^2-1)/2
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