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求多项式5m^2n+3mn^2-3m^2n-mn^2-4m^2n+3mn^2+1的值,其中m,n满足(m-2)^2+|n+1/3|=0
人气:273 ℃ 时间:2019-10-25 05:23:51
解答
(m-2)^2+|n+1/3|=0(m-2)^2=0m=2|n+1/3|=0n=-1/35m^2n+3mn^2-3m^2n-mn^2-4m^2n+3mn^2+1=5m^2n-4m^2n-3m^2n+3mn^2-mn^2+3mn^2+1=-2m^2n+5mn^2+1=5mn^2-2m^2n+1=mn(5n-2m)+1=-1/3*2(-1/3*5-2*2)+1=-2/3*(-5/3-4)+1=-2/3...
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