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3sinB-sin(2X+B)=0,则tan(X+B)-2tanX=
人气:465 ℃ 时间:2020-03-31 13:59:44
解答
sinB=sin(X+B-X)=sin(X+B)cosX-cos(X+B)sinXsin(2X+B)=sin(X+B+X)=sin(X+B)cosX+cos(X+B)sinX代入3sinB-sin(2X+B)=0得 2sin(X+B)cosX-4cos(X+B)sinX=02tan(X+B)-4tanX=0tan(X+B)-2tanX=0
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