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tanx=1,3sinb=sin(2x+b),求tan(x+b)
人气:303 ℃ 时间:2020-04-09 10:17:28
解答
3sin(x+b-x)=sin(x+b)cosx+cos(x+b)sinx 3sin(x+b)cosx-3cos(x+b)sinx=sin(x+b)cosx+cos(x+b)sinx 2sin(x+b)cosx=4cos(x+b)sinx tan(x+b)=2tanx=2
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