ln(lnx)的x次幂如何求导?_其他解答

ln(lnx)的x次幂
如何求导?

人气：411 ℃　时间：2020-05-27 05:57:48

解答

{[In(In)]^x}'
=x*[In(In(x)]^(x-1)*[In(Inx)]'
=x*[In(In(x)]^(x-1)*[1/Inx]*[Inx]'
=x*[In(In(x)]^(x-1)*[1/Inx]*1/x
=[In(In(x)]^(x-1)/Inx.