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用sina表示sin3a
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人气:158 ℃ 时间:2020-09-15 19:01:57
解答
sin3a=sin(2a+a)=sin2acosa+cos2asina
=2sina(cosa)^2+[1-2(sina)^2]sina
=2sina[1-(sina)^2]+sina-2(sina)^3
=2sina-2(sina)^3+sina-2(sina)^3
=3sina-4(sina)^3
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