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计算 [(2/3x)-(2/x+y)(x+y/3x-x-y)]÷(x-y/x) [1/(a+b)²-1/(a-b)²]÷(1/a+b - 1/a-b)
一:[(2/3x)-(2/x+y)(x+y/3x-x-y)]÷(x-y/x)
二:[1/(a+b)²-1/(a-b)²]÷(1/a+b - 1/a-b)
人气:381 ℃ 时间:2020-06-26 21:35:36
解答
一:[(2/3x)-(2/x+y)(x+y/3x-x-y)]÷(x-y/x)=[(2/3x)-2/(2x-y)]÷(x-y/x)=2/(3(x-y))-2x/(3(2x-y)(x-y))=(2(2x-y)-2x*3)/(3(2x-y)(x-y))=(-2(x+y))/(3(2x-y)(x-y))=(-2x-2y)/(6x^2-9xy+3y^2)二:[1/(a+b)...
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