∵|a+b+5|+（a+2）2=0，∴a+b+5=0，a+2=0，解得：a=-2，b=-3，∴3a2b-[2a2b-（3ab-a2b）-4a2]-2ab=3a2b-[2a2b-3ab+a2b-4a2]-2ab=3a2b-2a2b+3ab-a2b+4a2-2ab=ab+4a2=（-2）×（-3）+4×（-2）2=6+16=22．...