已知2x-y=10,求式子[(x^2+y^2)-(x-y)^2+2y(x-y)]÷2y
人气：330 ℃ 时间：2020-02-01 06:05:38
解答
=[x^2+y^2-(x^2-2xy+y^2)+2xy-2y^2]÷2y
=[2xy+2xy-2y^2]÷2y
=[4xy-2y^2]÷2y
=2x-y
=10
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