> 数学 >
cosx=1/7,cos(x-y)=13/14,0<y<x<π/2.求y
人气:385 ℃ 时间:2020-04-10 04:03:36
解答
由题意知:cosx=1/7 cos(x-y)=13/14则通过计算可得:sinx=4√3/7 sin(x-y)=3√3/14用余弦公式:cosx·cos(x-y)+sinx·sin(x-y)=cos[x-(x-y)]=cosy即cosy=(1/7·13/14)+(4√3/7·3√3/14)=1/2cosy=0.5 y=π/3...
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版