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数学
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如何解决以下等式:1)5x-4y+3z=15 6x+2y+9z=13 7x+6y-6z=6 2)5x-4y-6z=21 -2x+3y+4z=-15 3x-7y-5z=15
人气:462 ℃ 时间:2020-01-29 09:51:24
解答
(一)5x-4y+3z=15 (1)
6x+2y+9z=13 (2)
7x+6y-6z=6 (3)
(2)乘以2加(1)得17x+21z=41
(2)乘以3减(3)得11x+33z=33
解得:x=2 y=-1 z=1/3
(二)5x-4y-6z=21 (1)
-2x+3y+4z=-15 (2)
3x-7y-5z=15 (3)
(1)乘以3减(2)乘以4 得:7x-2z=3
(2)乘以7减(3)乘以3 得:5x-13z=60
解得:x=-1 y=1 z=-5
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(1) 4x-9z=17 3x+y+15z=18 x+2y+3z=2 (2)2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13
2) 4x-9z=17 3x+y+15z=18 x+2y+3z=2 (3) 2x+4y+3z=9 3x-2y+5z=11 5x-6y+7z=13
X+2Y-9Z=0,X-2Y-5Z=0(X,Y,Z不等于0),求代数式X平方-4Y平方+9Z平方,分之,2X平方+3Y平方+7Y平方值
解方程组2x+4y+3z=9, ①3x−2y+5z=11, ②5x−6y+7z=13. ③.
解方程组2x+4y+3z=9, ①3x−2y+5z=11, ②5x−6y+7z=13. ③.
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