你的意思是不是∫[d(x+1)]/[(x+1)^2+(√2)^2] =1/√2 arctan[(x+1)/√2] +C ?注意∫[d(x+1)] /[(x+1)^2+(√2)^2]=∫ [d(x+1)/2] / [(x/√2+1/√2)^2+ 1]=1/√2* ∫ [d(x/√2+1/√2) ] / [(x/√2+1/√2)^2+ 1] 令...