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用十字相乘法因式分解
5-7(a+1)-6(a+1)^2
-4x^3 +6x^2 -2x
6(y-z)^2 +13(z-y)+6
人气:477 ℃ 时间:2020-01-20 00:08:22
解答
5-7(a+1)-6(a+1)^2
=-[6(a+1)^2+7(a+1)-5]
=-[2(a+1)-1][3(a+1)+5]
=-(2a+1)(3a+8);
-4x^3 +6x^2 -2x
=-2x(2x^2-3x+1)
=-2x(x-1)(2x-1);
6(y-z)^2 +13(z-y)+6
=6(z-y)^2+13(z-y)+6
=[2(z-y)+3][3(z-y)+2]
=(2z-2y+3)(3z-3y+2).
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