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Acos(wt + u) +Bcos(wt + z)
怎么化简成一个cos的函数呀
人气:362 ℃ 时间:2020-04-15 18:18:22
解答
Acos(wt + u) +Bcos(wt + z) ={A2+B2+2ABcos(u-z)}1/2*cos{wt-π/2+arctan-(Acosu+Bcosz)/(Asinu+Bsinz)}
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