(3x^2-14x+14)/(x^2-6x+8)≥1[(3x^2-14x+14)-(x^2-6x+8)]/(x^2-6x+8)≥0(x^2-4x+3)/(x^2-6x+8)≥0∴(x-1)(x-3)/[(x-2)(x-4)]≥0∵(x-1)(x-3)/[(x-2)(x-4)]=0的四个实数根是1,2,3,4∴解是:x≤1,2＜x≤3,x＞4...